Question

How do you solve `0 = x^2 + 4x + 4` graphically and algebraically?

Answer 1

`x = -2`

Explanation:

Algebraically: factorise and then solve each factor = 0.

`(x+2)(x+2) = 0`

`x+2 = 0 rArr x =-2" both give the same answer"`

Graphically:
Draw the graph of `color(blue)(y) = x^2 +4x +4`
This will be a parabola.

To solve `x^2 +4x+4 = color(blue)(0)` , read the point(s) from the graph where the parabola cuts the `x`-axis.

The `x`-axis is the line where `color(blue)(y=0)`

The parabola will intersect (touch) at only point where `x = -2`graph{x^2+4x+4 [-10, 10, -5, 5]}