Question

How do you find the derivative of `ln((x^2)(e^x))`?

Answer 1

Apply the additive property of logs hence we have that

`ln(x^2*e^x)=ln(x^2)+ln(e^x)=2*lnx+x`

Hence the derivative is

`d(2*lnx+x)/dx=2/x+1`

for values of `x>0`