How do you find the inverse of #y=log(x-3)#?

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Answer 1 · 2016-08-12T21:23:28

Switch around the x and y values:

#y = log(x - 3)#

#x = log(y - 3)#

#10^x = y - 3#

#y = 10^x + 3#

#f^-1(x) = 10^x + 3#

Hopefully this helps!