How do you factor #9g^2-12g+4#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Deepak G. Aug 13, 2016 #=(3g-2)(3g-2)# Explanation: #9g^2-12g+4# #=9g^2-6g-6g+4# #=3g(3g-2)-2(3g-2)# #=(3g-2)(3g-2))# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1626 views around the world You can reuse this answer Creative Commons License