Question

How do you find all the roots of `f(x) = 3x^2 + 18x + 27`?

Answer 1

`f(x)` has zero `x=-3` of multiplicity `2`

Explanation:

`f(x) = 3x^2+18x+27`

`=3(x^2+6x+9)`

`= 3(x^2+2(3)x+3^2)`

`= 3(x+3)^2`

So the zeros of `f(x)` are both `-3`, i.e. `x=-3` is a zero with multiplicity `2`.