Question

What is the range of `f(x)=3sqrt(x+3)-1`?

Answer 1

f(x) ≥ -1, where x is real.

Explanation:

minimum value for term 1 is zero, when x= -3, here f(x) = -1 (minimum)
x cannot be less than -3. Then as x tends to infinity, f(x) tends to infinity.