How do you simplify #((3a)^2b^-3)/(b^-2)#?

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Answer 1 · 2016-08-15T22:13:49

#(9a^2)/b#

There are different laws of indices being used here. It does not matter in what order you apply the laws.

#(color(red)((3a)^2)color(blue)(b^-3))/(color(green)(b^-2))#

I like to get rid of the negative indices first.

#(color(red)((3a)^2)color(green)(b^2))/(color(blue)(b^3))#

Remove the brackets.

#(color(red)(9a^2)color(green)(b^2))/(color(blue)(b^3))#

Simplify by subtracting indices of like bases. (3-2=1)

#(9a^2)/b#