Question

How do you solve `4log_5(x+1)=4.8`?

Answer 1

`x~=5.8986`

Explanation:

`4log_5(x+1)=4.8`

`log_5(x+1) = 4.8/4 = 1.2`

`x+1 = 5^1.2 ~= 6.8986`

`x=~= 6.8986-1 ~= 5.8986`