How do you solve #-4y+16=4#?

2 Answers
Aug 16, 2016

y = 3

Explanation:

-4y = 4 - 16 (subtract 16 from both sides)
-4y = -12 (simplify RHS)
y = 3 (divide both sides by -4)

Aug 16, 2016

#y=3#

Explanation:

To solve this equation, isolate the - 4y term on the left of the equation while having numeric values on the right.

To do this, subtract 16 from both sides.

#rArr-4ycancel(+16)cancel(-16)=4-16#

we are left with #-4y=-12#

now divide both sides by - 4.

#(cancel(-4)^1 y)/cancel(-4)^1=(-12)/(-4)rArry=3" is the solution"#