Question

How do you solve `cscx-2=0`?

Answer 1

`pi/6 + 2kpi`
`(5pi)/6 + 2kpi`

Explanation:

`csc x - 2 = 0`
`1/(sin x) - 2 = 0`
`(1 - 2sin x)/sin x = 0`
1 - 2sin x = 0 --> (condition sin x different to zero)
`sin x = 1/2`
Trig table and unit circle give 2 solution arcs:
a. `x = pi/6 + 2kpi`
b. `x = (5pi)/6 + 2kpi`