Question

How do you differentiate `y=1/e^x`?

Answer 1

`dy/dx=-e^-x=-1/e^x`

Explanation:

differentiate using the `color(blue)"power rule and chain rule"`

`y=1/e^x=e^-x`

`rArrdy/dx=e^-x.d/dx(-x)=-e^-x=1/e^x`