How do you prove #sec2theta=sec^2theta/(2-sec^2theta)#?

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Answer 1 · 2016-08-19T22:24:25

#"To prove: "sec2theta=sec^2theta/(2-sec^2theta)#

#RHS=sec^2theta/(2-sec^2theta)#

#=(cos^2thetasec^2theta)/(cos^2theta(2-sec^2theta))#

#=1/(2cos^2theta-cos^2thetasec^2theta)#

#=1/(2cos^2theta-1)#

#=1/cos(2theta)=sec2theta=LHS#

PROVED