How do you solve #-6(-2x+2)+4(3+4x)=28# using the distributive property?
1 Answer
Aug 22, 2016
x = 1
Explanation:
The
#color(blue)"distributive property"# means multiply each of the terms inside the bracket by the number outside the bracket.In general terms this can be shown as.
#color(red)(|bar(ul(color(white)(a/a)color(black)(a(b+c)=ab+ac)color(white)(a/a)|)))#
#rArr(-6xx-2x)+(-6xx2)+(4xx3)+(4xx4x)=28#
#rArr12x-cancel(12)+cancel(12)+16x=28#
#rArr28x=28#
#(cancel(28)^1 x)/cancel(28)^1=cancel(28)^1/cancel(28)^1rArrx=1#