How do you integrate # (3-x)e^(-2x)#? Calculus Introduction to Integration Integrals of Exponential Functions 1 Answer GiĆ³ Aug 22, 2016 I found: #e^(-2x)[1/4-(3-x)/2]+c# Explanation: I would try integrating By Parts: Answer link Related questions How do you evaluate the integral #inte^(4x) dx#? How do you evaluate the integral #inte^(-x) dx#? How do you evaluate the integral #int3^(x) dx#? How do you evaluate the integral #int3e^(x)-5e^(2x) dx#? How do you evaluate the integral #int10^(-x) dx#? What is the integral of #e^(x^3)#? What is the integral of #e^(0.5x)#? What is the integral of #e^(2x)#? What is the integral of #e^(7x)#? What is the integral of #2e^(2x)#? See all questions in Integrals of Exponential Functions Impact of this question 6366 views around the world You can reuse this answer Creative Commons License