The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #275 ^o K#. If the pressure in the container changes to #25 Pa# with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2016-08-24T07:40:21

458.3 Kelvin (but there is no degrees sign)

1st situation: #P*V=n*R*T#

Here we have 15 Pa and 275 Kelvin (n, V and R are constants)

#15*V=n*R*275#

or #V/(n*R) = 275/15#

#V((n*R) = 18.3#

2nd situation:

(n, V and R constants)

#18.3 = T/25# T is temperature in Kelvin

Then #T=18.3*25#

T = 458.3 Kelvin