The gas inside of a container exerts $15 Pa$ of pressure and is at a temperature of $275 ^o K$ . If the pressure in the container changes to $25 Pa$ with no change in the container's volume, what is the new temperature of the gas?

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Answer 1 · 2016-08-24T07:40:21

458.3 Kelvin (but there is no degrees sign)

1st situation: $P*V=n*R*T$

Here we have 15 Pa and 275 Kelvin (n, V and R are constants)

$15*V=n*R*275$

or $V/(n*R) = 275/15$

$V((n*R) = 18.3$

2nd situation:

(n, V and R constants)

$18.3 = T/25$ T is temperature in Kelvin

Then $T=18.3*25$

T = 458.3 Kelvin

The gas inside of a container exerts 15 Pa15 Pa of pressure and is at a temperature of 275 ^o K275 ^o K. If the pressure in the container changes to 25 Pa25 Pa with no change in the container's volume, what is the new temperature of the gas?