Some very hot rocks have a temperature of #480 ^o C# and a specific heat of #180 J/(Kg*K)#. The rocks are bathed in #18 L# of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?
1 Answer
Aug 24, 2016
879 grams (based on the assumptions provided below)
Explanation:
Specific heat of water (at 100 degrees Celsius) = 4219 J/(kg*K)
18 L of boiling water = 17.244 kg (since at 100 degrees Celsius density of water = 958 g/L).
When you apply latent heat formula (mcDelta T) and suppose water temperature increased only 1 degrees Celsius, and further temperature of rocks dropped to 20 degrees Celsius,
m shows total mass of the rocks.
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