What is Hubble's constant in light years?

1 Answer
A. S. Adikesavan
Aug 24, 2016

Hubble constant #H_o = 71# km /sec/mega parsec = #4.5 X 10^(-12)# light year/sec/mega parsec.

Explanation:

Hubble constant #H_o = 71# km /sec/mega parsec

#71 km #

#= 71/499792=1.42 X 10^(-4)# light seconds

#=1.42 X 10^(-4)/(365.256 X 24 X 60 X 60)#

# = 4.5 X 10^(-12)# light years.

S0, #H_o = 4.5X 10^(-12)# light years/sec/mega parsec..
.

Related questions
See all questions in Expansion of the Universe
Impact of this question
3589 views around the world
You can reuse this answer
Creative Commons License