How do you simplify #100^(-1/2)#?

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Answer 1 · 2016-08-26T13:32:32

#1/(100)^0.5#

#1/(100)^0.5 = 1/10#

#=0.1#

Answer 2 · 2016-08-26T13:55:30

#1/10#

There are 2 different laws of indices being used here.

A negative index #larr "use the reciprocal"#
A fraction in the index #larr " same as a root"#

It does not matter which law you apply first.
I prefer to get rid of the negative index first.

#100^(-1/2) = 1/(100^(1/2))#

#1/(100^(1/2)) = 1/sqrt100#

=#1/10#