Question

How do you identify all asymptotes or holes and intercepts for `f(x)=(2x-3)/(3x+1)`?

Answer 1

There is an asymptote at x =`-1/3`

Explanation:

1 divided by 0.10=10. Or how many 0.1s can you get in 1
1 divided by 0.01 =100....
The smaller the divisor gets, the bigger the answer

In the limit as the divisor approaches zero the result approaches infinity and that is where we have an asymptote on the graph

So as 3x+1 approaches zero the function approaches infinity

Asymptote where 3x+1=0 or x =`-1/3`