How do you solve the quadratic #x^2+4=0# using any method?

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Answer 1 · 2016-08-26T18:43:42

#x=-2i# or #x=2i#

#x^2+4=0#

#hArrx^2-(-4)=0# or

as #i^2=-1# and hence

#x^2-(2i)^2=0# or

#(x+2i)(x-2i)=0# or

#x+2i=0# or#x-2i=0#

i.e. #x=-2i# or #x=2i#