Question #eedef

1 Answer
Aug 27, 2016

It is assumed that the given reaction is a gaseous one as it deals with #K_p# and the reversible reaction is represented by the following equation

#H_2(g)+I_2(g)rightleftharpoons2HI#

We know that the relation between #K_p and K_c# of agaseous reaction is

#K_p=K_c(RT)^(Deltan)....(1)#

Where #T->"Temperayure of the reaction in Kelvin"#

#R->"Universal gas constant"#

#Deltan->"Total no. of moles of gaseous product"- "Total no. of moles of gaseous reactants"#

For the given reaction

#Deltan=n_(HI(g))-n_(H_2(g))-n_(I_2(g))=2-1-1=0#

So by equation(1)

#K_p=K_c(RT)^(Deltan)=K_c(RT)^0=K_c=50#