How do you multiply #(4x^2-4y^2)^2#? Algebra Polynomials and Factoring Special Products of Polynomials 1 Answer Deepak G. Aug 28, 2016 #=16x^4+16y^4-32x^2y^2# Explanation: #(a-b)^2=a^2+b^2-2ab# Similarly #(4x^2-4y^2)^2# #=(4x^2)^2+(4y^2)^2-2times4x^2times4y^2# #=16x^4+16y^4-32x^2y^2# Answer link Related questions What are the Special Products of Polynomials? What is a perfect square binomial and how do you find the product? How do you simplify by multiplying #(x+10)^2#? How do you use the special product for squaring binomials to multiply #(1/4t+2 )^2#? How do you use the special product of a sum and difference to multiply #(3x^2+2)(3x^2-2)#? How do you evaluate #56^2# using special products? How do you multiply #(3x-2y)^2#? How do you factor # -8x^2 +32#? How do you factor #x^3-8y^3#? How do you factor # x^3 - 1#? See all questions in Special Products of Polynomials Impact of this question 1493 views around the world You can reuse this answer Creative Commons License