A container with a volume of #18 L# contains a gas with a temperature of #280^o C#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-08-29T12:27:10

We use Charles' Law: #V_1/T_1=V_2/T_2#, where #T# is quoted using Absolute Temperature.

The container was clearly a piston, because its volume changed during the experiment.

#T_1=280+273K=553K#; #T_2=360+273K=633K#

#V_2=(18*Lxx633*K)/(553*K)# #=# #??L#

Reasonably, volume has increased.