How do you solve #-10e^(2-2b)-6=-66#?

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Answer 1 · 2016-08-31T13:45:01

#b=0.104#

#-10e^(2-2b)-6=-66#

#hArr-10e^(2-2b)=-66+6# or

#e^(2-2b)=(-60)/(-10)=6# or

#2-2b=ln6# or

#2b=2-ln6# or

#b=1-ln6/2=1-1.792/2#

= #1-0.896=0.104#