How do you determine if #f(x) = 8x^3 + 3# is an even or odd function?

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Answer 1 · 2016-09-01T02:02:06

#f(x)# is neither odd nor even.

If a function #f(x)# is even than #f(-x)=f(x)#

and if it is odd than #f(-x)=-f(x)#.

As #f(x)=8x^3+3#,

#f(-x)=8(-x)^3+3#

= #-8x^3+3# and hence

#f(-x)# is neither equal to #f(x)# nor equal to #-f(x)#.

Hence, #f(x)# is neither odd nor even.