The concentration of carbon monoxide in an urban apartment is 48 #mu#g/#m^3#. What mass of carbon monoxide in grams is present in a room measuring 10.6 ft X 14.8 ft X 20.5 ft?

1 Answer
anor277
Sep 1, 2016

Approx. #5# #mg#

Explanation:

#"1 metre = 3.048 feet"#

Volume of room #=# #10.6xx14.8xx20.5*ft^3xx1/(3.048*ft*m^-1)^3#

#=# #113.57*m^3#

And thus mass of #CO# #=# #113.57*m^3xx48xx10^-6*g*m^-3#

#=# #5.45xx10^-3g#

Do not assume that I have got my arithmetic right; you are obliged to check this result.

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