How do you solve #ln10+ln(5x-2)=3#?

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Answer 1 · 2016-09-02T21:19:24

#x=0.80172#

#ln10+ln(5x-2)=3#

#hArrln(10×(5x-2))=3# or

#ln(50x-20)=3#

Hence #e^3=50x-20# or

#50x=e^3+20# or

#x=(20.086+20)/50# or

#x=40.086/50=0.80172#