How do you write the equation of a line given (-4,3) (4,-3)?

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Answer 1 · 2016-09-04T14:09:30

#6x+8y=0#

The equation of a line joining points #(x_1,y_1)# and #(x_2,y _2)# is given by

#(y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)#

Hence equation of line joining #(-4,3)# and #(4,-3)# is

#(y-3)/(-3-3)=(x-(-4))/(4-(-4))# or

#(y-3)/(-6)=(x+4)/8# or

#8y-24=-6x-24# or

#6x+8y=0#