How do you write #2^-3/2^4# using only positive exponents?

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Answer 1 · 2016-09-04T14:57:17

#1/2^7#

There are 2 laws of indices that we can use here.

Subtract the indices, or to get rid of the negative index,

#2^-3/2^4 = 1/(2^(4-(-3))#

=#1/2^7#

OR

#2^-3/2^4 = 1/(2^4 xx2^3)#

=#1/2^7#

Answer 2 · 2016-09-04T15:02:17

We have: #(2^(- 3)) / (2^(4))#

Using the laws of exponents:

#= 2^(- 3 - 4)#

#= 2^(- 7)#

#= (1) / (2^(7))#