How do you write a quadratic equation in standard form with the given root(s) 3, 2/5?

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Answer 1 · 2016-09-05T01:39:31

#5x^2-17x+6=0#

If the roots of an equation are #a# and #b#, the equation would be

#p(x-a)(x-b)=0#, where #p# is any constant

As roots are #3# and #2/5# the equation is

#(x-3)(x-2/5)=0# i.e.

#x^2-2/5 x-3x+6/5=0# or

#x^2-17/5x+6/5=0# or

#5x^2-17x+6=0#