How do you find the derivative of #e^(x-1)#?

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Answer 1 · 2016-09-05T12:37:30

#e^(x - 1)#

We have: #e^(x - 1)#

This expression can be differentiated using the "chain rule".

Let #u = x - 1 => u' = 1# and #v = e^(u) => v' = e^(u)#:

#=> (d) / (dx) (e^(x - 1)) = 1 cdot e^(u) #

#=> (d) / (dx) (e^(x - 1)) = e^(u)#

We can now replace #u# with #x - 1#:

#=> (d) / (dx) (e^(x - 1)) = e^(x - 1)#