Question

What is the perimeter of a triangle with corners at `(6 ,0 )`, `(9 ,2 )`, and `(5 ,4 )`?

Answer 1

Perimeter is `12.2008`

Explanation:

To find the perimeter of a triangle with corners at `(6,0)`, `(9,2)` and `(5,4)` we need length of each of the sides, which are distance between pair of points and are

`a=sqrt((9-6)^2+(2-0)^2)=sqrt(9+4)=sqrt13=3.6056`

`b=sqrt((5-9)^2+(4-2)^2)=sqrt(16+4)=sqrt20=4.4721` and

`c=sqrt((5-6)^2+(4-0)^2)=sqrt(1+16)=sqrt17=4.1231`

Hence perimeter is `3.6056+4.4721+4.1231=12.2008`