How do you factor and solve #2x^2=5x+12#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Nityananda · EZ as pi Sep 6, 2016 #x = 4 or x = -3/2# Explanation: #2x^2 - 5x -12 =0# or, #2x^2 - 8x + 3x - 12 = 0# or, # 2x(x - 4) + 3(x - 4) = 0# or, #(x - 4)(2x + 3) = 0# #rarr x = 4 and x = - 3/2# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1238 views around the world You can reuse this answer Creative Commons License