How do you evaluate #cos(pi+pi/3)#?
1 Answer
Sep 9, 2016
(- 1/2)
Explanation:
Use the trig identity:
cos (a + b) = cos a.cos b - sin a.sin b
Trig table of special arcs -->
(- 1/2)
Use the trig identity:
cos (a + b) = cos a.cos b - sin a.sin b
Trig table of special arcs -->