Question

Question #91d1f

Answer 1

Let the density of water be `1g/(mL)`

So the volume of `56g` of water =`56mL=0.056L`

Volume of alcohol in the mixture `0.17L`

So total Volume of the mixture `0.17L+0.056L=0.226L`

So the concentration of water in percent by volume `=0.056/0.226xx100=24.78%`

And the concentration of alcohol in percent by volume `(100-24.78)%=75.22%`