How do you solve #5p^2-15p=0#?

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Answer 1 · 2016-09-11T12:46:23

#p = 0, 3#

We have: #5 p^(2) - 15 p = 0#

Let's factorise the equation:

#=> 5 p (p - 3) = 0#

As we now have a product that is equal to zero, either one of the multiples must be equal to zero:

#=> 5 p = 0#

#=> p = 0#

or

#=> p - 3 = 0#

#=> p = 3#

Therefore, the solutions to the equation are #p = 0# and #p = 3#.

Answer 2 · 2016-09-11T12:50:18

#5p²-15p=0#
#5p(p-3)=0#
#5p=0, p-3=0#
#p=0/5, p=0+3#
#p=0, p=3#
#S.S{0 or 3}#