Question

`2NaN_3(s) -> 2Na(s) + 3N_2(g)` Given the equation, how many moles of `N_2` are produced by the decomposition of 1.50 mol of `NaN_3`?

Answer 1

2.25mol.

Explanation:

The equation tells you that for every 2 moles of `NaN_3` decomposed, you get 3 moles of `N_2` out.

So simply take the 1.5 mol and divide by two, then multiply by 3.