Question

How do you solve `abs(cosx)=1/2` in the interval [0,360]?

Answer 1

Solution is `x=60^0,120^0,240^0,300^0`[

Explanation:

1) `|cosx|=1/2 or cosx=1/2; Cos 60^0=1/2 ; cos 300=1/2 :. x=60^0,300^0`
2) `|cosx|=1/2 cosx= -1/2; Cos 120^0=-1/2 ; cos 240=-1/2 :. x=120^0,240^0`
So solution is `x=60^0,120^0,240^0,300^0`[Ans]