A container with a volume of #48 L# contains a gas with a temperature of #210^o K#. If the temperature of the gas changes to #80 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-09-15T01:13:10

Use Charles' Law to get a new volume of #18.3L#

Charles' Law for an ideal gas is that for a given mass and constant pressure, #V propT#.

To solve problems, this can be written as

#V_1/T_1 =V_2/T_2#

In this problem #V_1=48L#, #T_1=210K#, #T_2=80K# and #V_2=?#

#48/210=V_2/80#

Cross multiply (multiply the numerator of one side by the denominator of the other side)

#210*V_2=48*80#

#210V_2=3840#

Divide both sides by 210
#(210V_2)/210=3840/210#

#V_2=18.3L#