Question

How do you describe the nature of the roots of the equation `x^2+4x=96`?

Answer 1

8 and -12

Explanation:

Bring equation to standard form:
`y = x^2 + 4x - 96 = 0`
`D = b^2 - 4ac = 16 + 384 = 400 > 0` --> `d = +-20`
Since D > 0, there are 2 real roots. The roots have opposite signs (ac > 0).
`x = -b/(2a) +- d/(2a) = -4/2 +- 20/2 = -2 +- 10.`
x1 = -2 + 10 = 8
x2 = -2 - 10 = -12