Question

How do you find the number of complex, real and rational roots of `2x^2+5x+3=0`?

Answer 1

There are two rational roots `: -1, -3/2`.

Explanation:

`2x^2+5x+3=0`

`:. ul(2x^2+2x)+ul(3x+3)=0`

`:. 2x(x+1)+3(x+1)=0`

`:. (x+1)(2x+3)=0`

`:. x=-1, or, x=-3/2`

Thus, there are two rational roots `: -1, -3/2`.