Question

How do you find the equation of the circle given Center (8,-8), Radius 1/3?

Answer 1

`9x^2+9y^2-144x+144y+1151=0`

Explanation:

Circle with the given center at `(8,-8)` and radius `1/3`,

is the locus of a point that moves so that it is always at a distance of `1/3` from point `(8,-8)`

Hence equation is `(x-8)^2+(y-(-8))^2=(1/3)^2`

or `x^2-16x+64+y^2+16y+64=1/9`

or `9x^2+9y^2-144x+144y+9xx(64+64)-1=0`

or `9x^2+9y^2-144x+144y+1151=0`

graph{9x^2+9y^2-144x+144y+1151=0 [4.894, 9.894, -8.68, -6.18]}