Question

A gas cylinder with a volume of 3.00 `dm^3` contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder?

Answer 1

`P~=11*atm`

Explanation:

From the Ideal Gas Law: `P=(nRT)/V` `=` `(8.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx50.0*cancel(K))/(3.0*cancel(dm^3)xx1*cancelL*cancel(dm^-3))`.

Given the low temperature, and the small volume of the container, this value is liable to differ from the actual pressure measured in the cylinder. It is a first approximation.