Question

If `15 L` of a gas at room temperature exerts a pressure of `8 kPa` on its container, what pressure will the gas exert if the container's volume changes to `3 L`?

Answer 1

The gas will exert a pressure of `40kPa`

Explanation:

Let's identify the known and unknown variables:

`color(violet)("Knowns:")`
- Initial Volume
- Final Volume
- Initial Pressure

`color(orange)("Unknowns:")`
- Final Pressure

We can obtain the answer using Boyle's Law

The numbers 1 and 2 represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by `V_2` in order to get `P_2` by itself like this:
`P_2=(P_1xxV_1)/V_2`

Now all we do is plug in the values and we're done!

`P_2= (8kPa xx 15cancel"L")/(3\cancel"L")` = `40kPa`