How do you combine #2/(4z^2-12z+9)-(z+1)/(2z^2-3z)#?

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Answer 1 · 2016-09-20T19:11:08

#(-2z^2+3z+3)/(z(2z-3)(2z-3))#

In a question involving algebraic fractions, no matter what the operation is, factorize first.

#2/(4z^2-12z+9)-(z+1)/(2z^2-3z)#

#2/((2z-3)(2z-3)) - (z+1)/(z(2z-3))" "larr #find the LCD

=#(2z -(z+1)(2z-3))/(z(2z-3)(2z-3)) " "larr# make equivalent fractions

#(2z -(2z^2-3z+2z-3))/(z(2z-3)(2z-3))" "larr# simplify the numerator

#(2z -2z^2+3z-2z+3)/(z(2z-3)(2z-3))#

#(-2z^2+3z+3)/(z(2z-3)(2z-3))#