A container with a volume of #6 L# contains a gas with a temperature of #720^o K#. If the temperature of the gas changes to #480 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-09-21T22:10:31

Use Charles' Law to find the new volume is #4L#.

According to Charles' Law, in an ideal gas at constant pressure, volume is directly proportional to temperature. The relationship can be expressed as

#V_1/T_1=V_2/T_2#

#V_1=6L#, #T_1=720K#, #V_2=#?, #T_2=480K#

#6/720=V_2/480#

Cross multiply:

#6*480=720*V_2#

Divide both sides by #720#

#(6*480)/720 =(720*V_2)/720#

#V_2=4L#