How many geometric isomers exist for the molecule $C H_{3} - C H = C H - C H = C H - C H_{3}$ $CH_3-CH=CH-CH=CH-CH_3$ ?

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Answer 1 · 2016-09-23T17:50:42

There are three geometric isomers of hexa-2,4-diene.

The four possibilities are $(E, E)$ $(E,E)$ , $(E, Z)$ $(E,Z)$ , $(Z, E)$ $(Z,E)$ , and $(Z, Z)$ $(Z,Z)$ .

However, $(E, Z)$ $(E,Z)$ and $(Z, E)$ $(Z,E)$ are identical.

$(2 E, 4 E) -hexa-2,4-diene$ $(2E,4E)"-hexa-2,4-diene"$

(2E,4E)-hexa-2,4-diene#

$(2 E, 4 Z) -hexa-2-4-diene$ $(2E,4Z)"-hexa-2-4-diene"$

(2E,4Z)-hexa-2-4-diene

$(2 Z, 4 Z) -hexa-2-4-diene$ $(2Z,4Z)"-hexa-2-4-diene"$

(2Z,4Z)-hexa-2-4-diene

How many geometric isomers exist for the molecule CH3−CH=CH−CH=CH−CH3CH_3-CH=CH-CH=CH-CH_3?