Question

How do you differentiate `y=3^sinx`?

Answer 1

`y = 3^sinx`

`lny = ln(3^(sinx))`

`lny = sinxln3`

`1/y(dy/dx) = (cosx xx ln3 + 0 xx sinx)`

`dy/dx = (ln3cosx)/(1/y)`

`dy/dx = y xx ln3cosx`

`dy/dx = 3^sinx xx ln3cosx`

`dy/dx = 3^sinxln3cosx`

Hopefully this helps!