How do you solve #d/-4+3=15#?
1 Answer
Sep 25, 2016
Explanation:
To eliminate the fraction on the left side along with the leading negative sign, multiply
#color(blue)"all terms"# by -4.
#cancel(-4)^1xxd/cancel(-4)^1+(-4xx3)=(-4xx15)#
#rArrd-12=-60# To solve for d, add 12 to both sides.
#d cancel(-12)cancel(+12)=-60+12#
#rArrd=-48" is the solution to the equation."#
