How do you solve the system #x^2-y-4=0# and #x^2+3y^2-4y-10=0#? Precalculus Solving Systems of Two Equations Solving by Substitution 1 Answer Cesareo R. Sep 25, 2016 #y = -1, x=pmsqrt(3)# #y = 2,x=pmsqrt(6)# Explanation: #{(x^2-y-4=0),(x^2+3y^2-4y-10=0):}# Substracting the first from the second #3(y^2-y-2)=0# with solutions #y = -1, x=pmsqrt(3)# #y = 2,x=pmsqrt(6)# Answer link Related questions What is a system of equations? What does it mean to solve a system of equations by substitution? How do I use substitution to find the solution of the system of equations #c+3d=8# and #c=4d-6#? How do you write a system of linear equations in two variables? How does a system of linear equations have no solution? How many solutions can a system of linear equations have? What is the final step of completing a solve by substitution problem? How do I use substitution to find the solution of the system of equations #4x+3y=7# and #3x+5y=8#? How do I use substitution to find the solution of the system of equations #y=2x+1# and #2y=4x+2#? How do I use substitution to find the solution of the system of equations #y=1/3x+7/3# and... See all questions in Solving by Substitution Impact of this question 1365 views around the world You can reuse this answer Creative Commons License